If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
s = (4/3)^3.14*r^3 // - (4/3)^3.14*r^3
s-((4/3)^3.14*r^3) = 0
s-(4/3)^3.14*r^3 = 0
x należy do R
x in (-oo:+oo)
| 1/3x-2/5y=10 | | 1/2x-2/5y=10 | | 8(2l+1)=81 | | y=1/2x^-15 | | x+3=4y+1 | | x^2-a(x+1)-b=0 | | X+125-x=250 | | 0x=125 | | 2cos^2(2x)+3cos^2x=2 | | y+y=576 | | 5x^2-4ax-a^2=0 | | h(x)=ln(x^3+4) | | 2x^4-3x^2-16x+24=0 | | cos(45)=3.9/x | | Y=(5x-1)*(4+3x) | | 5x-6y=4whatsx | | 8(2m-3)=-2(m-42) | | 6(-y+2)=2p+5 | | 2-(4p+3)=2p+5 | | -4(6+1)=-20x | | 2t+5=4t-1 | | 6g-5h-4g+2h=0 | | 18=x^2-11x-24 | | 0.07x+0.02y=0.35(12-x) | | 9x^2-8x-24=0 | | 6x+34=14-54 | | log(x^2-3)=0 | | 3(x+2)-x=4 | | 6^4/6^3×6^2 | | 7+2(3x-1)=29 | | 5t*t=80 | | 5(x+4)-2(x-1)=43 |